A survey is done among a population of 200 people who like either tea or coffee. It is found that 60% of the pop lation like tea and 72% of the population like coffee. Let $x$ be the number of people who like both tea & coffee. Let $m{\leq x\leq n}$, then choose the correct option.
Let Z be the set of all integers, and consider the sets $X=\{(x,y)\colon{x}^2+2{y}^2=3,\, x,y\in Z\}$ and $Y=\{(x,y)\colon x{\gt}y,\, x,y\in Z\}$. Then the number of elements in $X\cap Y$ is:
Out of a group of 50 students taking examinations in Mathematics, Physics, and
Chemistry, 37 students passed Mathematics, 24 passed Physics, and 43 passed
Chemistry. Additionally, no more than 19 students passed both Mathematics and
Physics, no more than 29 passed both Mathematics and Chemistry, and no more than
20 passed both Physics and Chemistry. What is the maximum number of students who
could have passed all three examinations?
There are two sets A and B with |A| = m and
|B| = n. If |P(A)| − |P(B)| = 112 then
choose the wrong option (where |A| denotes
the cardinality of A, and P(A) denotes the
power set of A)
In a survey where 100 students reported which subject they like, 32 students in total liked Mathematics, 38 students liked Business and 30 students liked Literature. Moreover, 7 students liked both Mathematics and Literature, 10 students liked both Mathematics and Business. 8 students like both Business and Literature, 5 students liked all three subjects. Then the number of people who liked exactly one subject is
Suppose $A_1,A_2,\ldots,A_{30}$ are 30 sets each with five elements and $B_1,B_2,B_3,\ldots,B_n$ are n sets (each with three elements) such that $\bigcup ^{30}_{i=1}{{A}}_i={{\bigcup }}^n_{j=1}{{B}}_i=S\, $ and each element of S belongs to exactly ten of the $A_i$'s and exactly 9 of the $B^{\prime}_j$'s. Then $n=$
In a class of 50 students, it was found that 30
students read "Hitava", 35 students read "Hindustan" and 10 read neither. How many
students read both: "Hitavad" and "Hindustan" newspapers?